4sin^2(2x)+8cos(2x)=7

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Solution for 4sin^2(2x)+8cos(2x)=7 equation: 


Simplifying
4sin2(2x) + 8cos(2x) = 7

Remove parenthesis around (2x)
4in2s * 2x + 8cos(2x) = 7

Reorder the terms for easier multiplication:
4 * 2in2s * x + 8cos(2x) = 7

Multiply 4 * 2
8in2s * x + 8cos(2x) = 7

Multiply in2s * x
8in2sx + 8cos(2x) = 7

Remove parenthesis around (2x)
8in2sx + 8cos * 2x = 7

Reorder the terms for easier multiplication:
8in2sx + 8 * 2cos * x = 7

Multiply 8 * 2
8in2sx + 16cos * x = 7

Multiply cos * x
8in2sx + 16cosx = 7

Reorder the terms:
16cosx + 8in2sx = 7

Solving
16cosx + 8in2sx = 7

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8in2sx' to each side of the equation.
16cosx + 8in2sx + -8in2sx = 7 + -8in2sx

Combine like terms: 8in2sx + -8in2sx = 0
16cosx + 0 = 7 + -8in2sx
16cosx = 7 + -8in2sx

Divide each side by '16osx'.
c = 0.4375o-1s-1x-1 + -0.5in2o-1

Simplifying
c = 0.4375o-1s-1x-1 + -0.5in2o-1

Reorder the terms:
c = -0.5in2o-1 + 0.4375o-1s-1x-1

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